PROGRAM NOTES
Puzzlet 18 set us to work
designing a Mixing Tank. It needs a base,
4 sides, but no top. External dimensions are all 1 metre
exactly.
It will be filled with fluid to a line 10 cm from the top.
The
volume of material used to make the tank must not exceed 5% of the
volume
of fluid in the Tank. What is the thickness of the material used,
to
the nearest tenth of a millimetre?
This poser needs a little analysis to derive its equation. Since it's
in
Puzzlet, you've no doubt guessed we need a computer program to solve
the
equation.
So, what do we know? Firstly, the volume of the tank
overall
is 1 cubic metre. Secondly, we can express its internal volume
and
permitted fluid volume in terms of material thickness. Finally,
we
can use the above to derive a formula for material volume. Since
the
material volume is 5% (maximum) of the fluid volume, we can combine
these
two and develop the final equation ready for the computer to do the
donkey
work. This is how it all goes together, using the abbreviation t
for
thickness:
Internal base width = (1 - 2*t) metres.
Internal base depth = (1 - 2*t) metres.
Internal max height = (1 - t) metres.
Therefore internal volume = (1 - 2*t)2(1
- t)
= (1 - t)*(1 - 4*t + 4*t2)
=
1 - 5*t
+ 8*t2
- 4*t3
cubic metres.
Now we can find material volume, since it is total volume
minus
internal volume. We've already seen that total volume is 1
cubic
metre. Therefore, material volume is:
1 - (
1 - 5*t
+ 8*t2
-
4*t3
)
=
4*t3 -
8*t2
+ 5*t cubic metres.
On to fluid volume, bearing in mind that the fluid height is 10
cm
below the top of the Tank.
Internal base width = (1 - 2*t) metres.
Internal base depth = (1 - 2*t) metres.
Fluid height = (1 - t - 0.1) = (0.9 - t) metres.
Therefore fluid volume = (0.9 - t)*(1 - 2*t)2
= 0.9 - 4.6*t + 7.6*t2 - 4*t3
cubic metres.
So now we have equations for fluid volume and material
volume.
We know that the latter must not exceed 5% of the
former.
This can be expressed as:
Fluid volume (minimum) = 20 * material volume.
Substituting the formulae derived above into this equation:
0.9 - 4.6*t + 7.6*t2
- 4*t3 = 20*(
4*t3 -
8*t2
+ 5*t)
Rearranging and multiplying out gives:
84*t3 - 167.6*t2 +
104.6*t
- 0.9 = 0
And so we come back to one of our old favourites, the cubic equation.
We've
encountered this before several times in Puzzlets, and used
various
ways to solve it. On one occasion,
Newton's
Rule was used, and that's the one deployed here. If you
want
an explanation of how this neat mathematical toy works, it's in the
Answer
to Puzzlet 5, which you can find by going to the Archives Page.